Quote:
Originally Posted by wmcinnes
I'm just restating what has been said but:
PF= True Watts/ Volts*Amperes
True Watts= 82w
Volts= 115v
Amps= 1.80a
PF= 82/207 = 0.396
You're pump output is only 40% of the power it is drawing. Not good, not efficient! haha
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There you go Steve. Another justification
You better change the motor if you want the consumption to cut to half! DC motors FYI!