ok,I didn;t want to confuse myself but sence you had to go there! :eek: I will play both sides of the coin.. if you change the intake so it is very small (ie. get rid of the suction strainer and put a extended pipe on it. it will help to creat a current in the tank. the problem is because of the chareristics of water flow it will not be as defined as the output. so you might be creating a 1200gph suction but as far a a current effect you might only notice the equivalance of say 200gph. see whare I am going?

yes you are sucking 1200 gal and throwing out 1200 gal but the main effect you will notice from the suction is a "psudo direction" of the output. ie. setting up a whirlpool in the tank :mrgreen:

Steve

Re: Intresting flow question
 

[quote="Canadian Man"]

I guess it is a slow day. The answer would involve a lot of physics, which is something I know little about. But as far as flow goes, you only need to ask any Anemone that has been sucked into a powerhead about this. :mrgreen:

If you plug the input on the 1200gph pump do you still get 1200 gph output? :smile:

I don't think it matters where the water comes from (input, eductor, etc) or where it goes to (nozzle, return, etc) I think you can only count the 1200gph total water movement. :cool:

No, pump curves are calculated on the output of the pump only. The water going into the pump can be counted, however, since it is drawing from the entire body of water, the water movement generated is insignificant. Essentially water velocity is approaching zero and therefore should not be calculated in a flow equation.

Pretty muddy, huh?